4x - 2x - 5 = 4 + 6x + 3 |
Goal is to isolate x on one side to be able to solve. |
2x - 5 = 7 + 6x |
Combine like terms. |
2x - 5 + 5 = 7 + 6x + 5 |
Add 5 to each side. |
2x = 12 + 6x |
Subtract 6x from each side. |
-4x = 12 |
Then, divide both sides by -4 |
x = -3 |
CHECK your solution by plugging back into the original equation. |
Disclaimer: I did not create nor do I own these videos. I have simply embedded them, courtesy of YouTube. (But I do think this teacher does a fantastic job with his video tutorial series.)
2(k - 5) + 3k = k + 6 |
Use the distributive property to simplify and combine like terms. |
2k - 10 + 3k = k + 6 |
Combine like terms. |
5k - 10 = k + 6 |
Then, add 10 to both sides. |
5k = 16 + k |
Then, subtract k from both sides. |
4k = 16 |
Then, divide both sides by 4 |
k = 4 |
CHECK your solution by plugging back into the original equation. |
Disclaimer: I did not create nor do I own these videos. I have simply embedded them, courtesy of YouTube. (But I do think this teacher does a fantastic job with his video tutorial series.)
Counting Numbers:
{1, 2, 3, 4, 5, 6, ...}
BY THE WAY, "..." notates continuation going up infinitely.
The set of Natural Numbers \( \mathbb{N}\ \ \) = {0, 1, 2 3, 4, 5, 6...}.
The set of Integers, \( \mathbb{Z}\ \ \) = {..., -3, -2, -1, 0, 1, 2, 3}.
The set of Rational numbers, \( \mathbb{Q}\ \ \) is the set of ratios of integers.
That is, every \(q \in \mathbb{Q}\ \)
is of the form:
\( q = \frac{n}{m} \ \)
With \( n, m \in \mathbb{Z}\ \) .
The set of Real Numbers \( \mathbb{R}\ \ \) is the set of limits of sequences of rational numbers.
A set is a collection of "elements," or "members," and each set is entirely determined by its members. If \[ x \]is a member of a set \[ U, \] we write \[ x \in U. \] In basic algebra, the elements of a set are usually numbers.
We can also designate a set by enclosing its members in braces , { }.